Concept of Hardy-Weinberg Equilibrium Explained
Before we start the Hardy-Weinberg equilibrium, let’s talk about the meaning of evolution. Does evolution mean the development of new species? Well, the answer is absolutely no. A slight change within a species from one generation to another over a long period of time can result in the gradual transition of new species.
Biological sciences define evolution as the sum total of all the genetically inherited changes in individuals who are the members of a population’s gene pool (the sum total of all the alleles in a population). It is clear that the effects of evolution are experienced by individuals, but it is the overall population that actually evolves. So, we can define evolution as the change in frequencies of alleles in the gene pool of a population.
In the early 20th century, English mathematician Godfrey Hardy and the German physician Wilhelm Weinberg independently provided the explanation of concept called Hardy-Weinberg Equilibrium. This theory states that a population’s allele and genotype frequencies are inherently stable unless some kind of evolutionary force is acting on the population, the population would carry the same alleles in the same populations generation after generation. Individuals in a population would look essentially the same and this would be unrelated to whether the alleles are dominant or recessive. However, this concept is true only when the five evolutionary forces are absent as these forces can disrupt the equilibrium. These five forces include:
- Natural Selection
- Mutation
- Genetic Drift
- Gene migration or gene flow
- Genetic recombination
It means, if the above five factors are absent in a population, no evolution will occur in that particular population. However, in a practical sense, it is not possible that any of these factors would not be present in nature. In other words, we can say that evolution is the inevitable result.
Hardy and Weinberg developed a simple equation that can be used to find the probable genotype frequencies in a population and changes if any can be tracked from one generation to another. This is known as the Hardy-Weinberg Equilibrium equation.
P2 + 2pq + q2 = 1 or, (p + q)2 = 1
Where p represents dominant allele A; q represents recessive allele a
In other words, p = AA + ½ Aa; q = aa + ½ Aa or p + q = 1
In the above equation, p2 is the predicted frequency of homozygous dominant (AA) people in a population; 2pq is the predicted frequency of heterozygous (Aa) people and q2 is the predicted frequency of homozygous recessive (aa) people.
It is interesting to note that only the frequency of homozygous recessive people can be calculated. As far as a dominant trait is considered, it is represented by either homozygous dominant (p2) or heterozygous (2pq). However, using the Hardy-Weinberg equation, we can also calculate the frequency of p2 and 2pq without any hassle. Since, p + q = 1 and p = 1-q where q is known, so we can calculate the frequency of p2 and 2pq easily.
Q1. In a given population, the percentage of homozygous recessive genotype (aa) is 36%. What would be the frequency of:
a) a allele
b) A allele
c) AA and Aa genotype
Solution: Since the percentage of recessive genotype is given (36%), it means q2 = 36% = 0.36
So, q = 0.6, and since q= a; the frequency of a = 60%
The frequency of A can be calculated from the equation p + q = 1
P = 1 – q
P = 1 – 0.6 = 0.4; so the frequency of A is 40%
The frequency of genotype AA and Aa
The frequency of AA equals to p2 (0.4x0.4 = 0.16) = 16%
The frequency of Aa equals 2pq = (2 x 0.4 x 0.6) = 0.48 = 48%
Q2. Sickle-cell anemia is a genetic disease. Normal homozygous individuals (SS) having normal red blood cells are susceptible to the malaria parasite. On the other hand, individuals with sickle-cell trait (ss) have red blood cells that easily collapse under deoxygenated condition. These individuals are resistant to malaria parasite as such parasites cannot grow in the sickle-celled red blood cells. Individuals with sickle-cell red blood cells often die because of the genetic defect. However, individuals with heterozygous condition (Ss) have some sickle-celled red blood cells, but not enough to cause mortality. Besides, malaria parasite can also survive within these partially defective red blood cells. In other words, a heterozygous condition is better than either of the homozygous conditions. If 9% of an African population is born with sickle-cell anemia (ss), what percentage of the population will be more resistant to malaria because they are heterozygous (Ss) for the sickle-cell gene?
Ans: ss = q2 = 9% = 0.09; q = 0.3
P = 1 – q = 1 – 0.3 = 0.7
2pq = 2 x 0.7 x 0.3 = 0.42 = 42 % (heterozygous carrier)